Find the equation for a parabola with given vertex and point.

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In summary, the equation for the parabola with vertex (-5,5) that passes through point (-3,17) is y=3(x+5)^2+5. This solution was found by plugging in the given points and using the fact that the vertex has only one root, giving the equation y=-b/2a.
  • #1
TonyC
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Vertex (-5,5) point (-3,17)

Equation for the parabola with the given vertex that passes through the given point.

I am stumped! Please help :bugeye:
 
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  • #2
well, look at this
you have a quadratic of the form ax^2+bx+c
so you have two points
so plug in y and x in for those two points:

5=25a-5b+c
and
17=9a-3b+c

but they also tell you that (-5, 5) is the vertex
which means that there, the solution only has one root; meaning that the x coordinate is equal to -b/2a
so then you have
-5=-b/2a

i think you should be able to solve for this now. perhapsably.
 
  • #3
Using what is provided, I have come up with:

y=3(x+5)^2+5
 
  • #4
TonyC said:
Using what is provided, I have come up with:

y=3(x+5)^2+5

Great. This is always the most insightful way to write the equation of a parabola.
As a check, you can easily see the vertex is at (-5,5). Putting x=-3 gives y=3(2^2)+5=17.
 

FAQ: Find the equation for a parabola with given vertex and point.

What is the equation for a parabola?

The standard form equation for a parabola is y = ax^2 + bx + c, where a is the coefficient of the squared term, b is the coefficient of the linear term, and c is the constant term.

How do you graph a parabola from its equation?

To graph a parabola from its equation, you can plot points by substituting different values for x and solving for y. Another method is to use the vertex form of the equation, y = a(x-h)^2 + k, where (h,k) is the vertex of the parabola. You can then plot the vertex and two other points to draw the parabola.

What is the significance of the coefficient a in the parabola equation?

The coefficient a determines the shape and direction of the parabola. If a is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. The value of a also determines the steepness of the curve. A larger absolute value of a results in a steeper curve.

How do you find the vertex, focus, and directrix of a parabola from its equation?

The vertex of a parabola can be found by using the formula h = -b/2a and k = c-b^2/4a, where (h,k) is the vertex. The focus can be found by using the formula (h,k+p), where p = 1/4a. The directrix is a horizontal line y = k-p or a vertical line x = h-p, depending on the orientation of the parabola.

What are some real-life applications of the parabola equation?

The parabola equation is used in various fields, such as physics, engineering, and economics. Some examples include the trajectory of a thrown object, the shape of satellite dishes, and the cost and revenue curves in business. The parabola also appears in architecture and design, such as in the shape of arches and suspension bridges.

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