Can you find a normal to the plane? It will point toward the center of the sphere (there will be two of them, though). And you know the radius of the sphere, so you should be able to find the center of the sphere.lolphysics3 said:Homework Statement
tangent to x-3y+4z+23=0 at (1,4,-3) with radius sqrt(26)
Homework Equations
The Attempt at a Solution
well i initially thought it's possible to set up a system of equations but it didn't work out.
The general form of the equation for a sphere is (x - h)^2 + (y - k)^2 + (z - l)^2 = r^2, where (h, k, l) represents the center of the sphere and r is the radius.
To find the center of a sphere given its equation, you can rewrite the equation in the general form and identify the values of h, k, and l. These values represent the coordinates of the center of the sphere.
Yes, you can find the radius of a sphere if you know its equation. Simply take the square root of the constant value on the right side of the equation.
The general form of a sphere's equation can provide information about the center and radius of the sphere. It can also be used to determine whether a given point is inside, outside, or on the surface of the sphere.
To graph a sphere from its general form equation, plot the coordinates of the center on a 3D coordinate plane. Then, use the radius to plot points on the surface of the sphere, creating a curved surface. You can also use technology, such as a graphing calculator, to visualize the sphere.