- #1
debrajr
- 4
- 0
Find the equation of the conicoid
\(\displaystyle 2x^2-y^2=z^2+2x-7\)
when the origin is shifted to
\(\displaystyle (2,-2,0)\)
and the axes are rotated so that the new axes have direction ratios
\(\displaystyle -1,0,1;1,-2,1;0,1,1\)
\(\displaystyle 2x^2-y^2=z^2+2x-7\)
when the origin is shifted to
\(\displaystyle (2,-2,0)\)
and the axes are rotated so that the new axes have direction ratios
\(\displaystyle -1,0,1;1,-2,1;0,1,1\)