- #1
blue_soda025
- 26
- 0
Find the equation of the hyperbola with centre at the origin and sketch the graph.
e. tranverse axis is on the y-axis and passes through the points R(4, 6) and S(1, -3)
How would I find a and b? I plugged in the coordinates in [tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex] and came up with two equations. The thing is, I get to the point where I have to take the square root of both sides, but one side is always negative. I thought you couldn't take the square root of a negative?
e. tranverse axis is on the y-axis and passes through the points R(4, 6) and S(1, -3)
How would I find a and b? I plugged in the coordinates in [tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex] and came up with two equations. The thing is, I get to the point where I have to take the square root of both sides, but one side is always negative. I thought you couldn't take the square root of a negative?