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chwala
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- Homework Statement
- See attached.
- Relevant Equations
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The question is as shown below. ( Text book question).
The textbook solution is indicated below.
Discussion;
Now they seemingly used ##r=1## to arrive at ##x=0.8+0.2y##. That is,
##y=-4+5x##
then, since ##r=1##, ...implying perfect correlation therefore,
##5x=4+y##
##x=0.8+0.2y##
My other way of doing this (as we we would not always have ##r=1##) would be;
##\bar x=a+b\bar y##
##b=\dfrac{S_{xy}}{S_{yy}}##=##\dfrac{87.5}{437.5}=0.2##
##a=\dfrac{21}{6}-\dfrac{0.2×81}{6}=0.8## therefore,
##x=0.8+0.2y##
Any other approach or insight is highly welcome.
The textbook solution is indicated below.
Now they seemingly used ##r=1## to arrive at ##x=0.8+0.2y##. That is,
##y=-4+5x##
then, since ##r=1##, ...implying perfect correlation therefore,
##5x=4+y##
##x=0.8+0.2y##
My other way of doing this (as we we would not always have ##r=1##) would be;
##\bar x=a+b\bar y##
##b=\dfrac{S_{xy}}{S_{yy}}##=##\dfrac{87.5}{437.5}=0.2##
##a=\dfrac{21}{6}-\dfrac{0.2×81}{6}=0.8## therefore,
##x=0.8+0.2y##
Any other approach or insight is highly welcome.
Last edited: