Find the flux (calculus problem)?

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In summary, the problem is to find the flux of F across surface S, where F = (x,2y,z), S is the part of the cone (x^2+z^2)^1/2=y inside of the cylinder x^2+z^2=1, and n points to the right. The relevant equation is ∫∫s F · dS and the attempt at a solution involves using the divergence theorem and converting to cylindrical coordinates. However, there is uncertainty about whether the base(s) of the cone are included and the outward direction of the flux. An exact statement of the problem is needed for an accurate calculation.
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Homework Statement



The directions for this calculus problem say find the flux of F across surface S (that is find the double integral F (ds)) where F = (x,2y,z), S is the part of the cone (x^2+z^2)^1/2=y inside of the cylinder x^2+z^2=1 and n points to the right.


Homework Equations



I'm pretty sure you need to use the divergence theorem here. So I guess ∫∫s F · dS is a relevant equation.

The Attempt at a Solution



Here is my work, along with the answer that I got. Please tell me if it is right.

∫∫s F · dS
= ∫∫∫ div F dV
= ∫∫∫ (1 + 2 + 1) dV
= 4 ∫∫∫ dV.

Now, convert this to cylindrical coordinates (with y playing the role of z):
4 ∫(θ = 0 to 2π) ∫(r = 0 to 1) ∫(y = 0 to r) r dy dr dθ
= 4 * 2π ∫(r = 0 to 1) r^2 dr
= 8π/3.
 
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  • #2
The divergence theorem applies to flux outward from a closed volume. You haven't mentioned anything about the base(s) of the cone. Also, in that case the outward direction wouldn't be to the right.

Perhaps you are meant to calculate the flux directly. And how about the part of the cone where y < 0, is that included?

An exact statement of the problem is needed to know what you are actually trying to calculate.
 

FAQ: Find the flux (calculus problem)?

What is a flux in calculus?

A flux in calculus is a measure of the flow of a vector field through a surface. It is represented by the integral of the dot product between the vector field and the surface's normal vector.

How is flux calculated?

The flux is calculated by taking the surface integral of the dot product between the vector field and the unit normal vector of the surface. This can be represented by the formula ∯ F · dA, where F is the vector field and dA is the differential element of the surface.

What is the difference between positive and negative flux?

A positive flux indicates that the vector field is flowing out of the surface, while a negative flux indicates that the vector field is flowing into the surface. This can be visualized by the direction of the normal vector with respect to the vector field.

How is flux used in real-world applications?

Flux is commonly used in physics and engineering to calculate the flow of fluid or heat through a surface. It can also be used in electromagnetism to calculate the flow of electric or magnetic fields through a given surface.

What is the relationship between flux and divergence?

The flux of a vector field is directly related to its divergence. The divergence measures the rate at which the vector field is flowing out or in at a given point, while the flux measures the overall flow through a surface. The divergence theorem states that the flux through a closed surface is equal to the volume integral of the divergence within the enclosed region.

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