- #1
CricK0es
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Hi all. I'm completely new to these forums so sorry if I'm doing anything wrong.
Anyway, I have this question...
Hi all. I'm completely new to these forums so sorry if I'm doing anything wrong.
Anyway, I have this question...
Find the Fourier series for the periodic function
f(x) = x^2 (-pi < x < pi), f(x) = f(x+2pi)
By considering the particular values x = 0 and x = +/- pi prove that
f(x) = x^2 (-pi < x < pi), f(x) = f(x+2pi)
By considering the particular values x = 0 and x = +/- pi prove that
∞^Σ (n=1) 1 / n^2 = pi^2 / 6
and
∞^Σ (n=1) (-1)^n / n^2 = -pi^2 / 12
I missed a couple of lectures due to illness so I'm not entirely sure what to do with this.
But I have worked through and found the FS itself. Whether it's right I really don't know...
= pi^2 / 3 + ∞^Σ (n=1) 4/n (-1)^n Cos(nx)
Again, I'm really sorry that it's all a bit messy but I'm still getting use to everything. I would like to learn how to use LaTeX to make equations easier/clearer also. But, regardless, I would really appreciate some guidance on how to proceed through the question. Many thanks
and
∞^Σ (n=1) (-1)^n / n^2 = -pi^2 / 12
I missed a couple of lectures due to illness so I'm not entirely sure what to do with this.
But I have worked through and found the FS itself. Whether it's right I really don't know...
= pi^2 / 3 + ∞^Σ (n=1) 4/n (-1)^n Cos(nx)
Again, I'm really sorry that it's all a bit messy but I'm still getting use to everything. I would like to learn how to use LaTeX to make equations easier/clearer also. But, regardless, I would really appreciate some guidance on how to proceed through the question. Many thanks
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