- #1
danago
Gold Member
- 1,123
- 4
Hi. The question wants me to find the inverse of [tex]
y = \frac{{x - 1}}{{x - 2}}
[/tex]
Heres my working for it:
[tex]
\begin{array}{l}
x = \frac{{y - 1}}{{y - 2}} \\
xy - 2x = y - 1 \\
xy - y = 2x - 1 \\
(x - 1)y = 2x - 1 \\
y = \frac{{2x - 1}}{{x - 1}} \\
\end{array}
[/tex]
The answer says something different though.
If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.
Thanks,
Dan.
y = \frac{{x - 1}}{{x - 2}}
[/tex]
Heres my working for it:
[tex]
\begin{array}{l}
x = \frac{{y - 1}}{{y - 2}} \\
xy - 2x = y - 1 \\
xy - y = 2x - 1 \\
(x - 1)y = 2x - 1 \\
y = \frac{{2x - 1}}{{x - 1}} \\
\end{array}
[/tex]
The answer says something different though.
If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.
Thanks,
Dan.