Harpazo said:Find the limit of 1/(n•cosn) as n tends to +∞.
I say the following:
1/[(∞)cos (∞)]
1/∞ = 0
The limit is 0.
The limit of 1/(n•cosn) as n tends to +∞ is 0. This means that as n gets larger and larger, the value of 1/(n•cosn) approaches 0.
To find the limit of 1/(n•cosn) as n tends to +∞, we can use the squeeze theorem or the ratio test. Alternatively, we can rewrite the expression as 1/(n•cosn) = 1/n * 1/cosn and take the limit of each term separately.
The value of the limit of 1/(n•cosn) as n tends to +∞ represents the behavior of the function as n approaches infinity. In this case, the function approaches 0 as n gets larger and larger.
Yes, the limit of 1/(n•cosn) as n tends to +∞ is always 0. This is because cosn oscillates between -1 and 1 as n increases, so the value of 1/(n•cosn) gets smaller and smaller.
Yes, the limit of 1/(n•cosn) as n tends to +∞ has applications in Fourier analysis and signal processing. It is also used in physics and engineering to study oscillatory systems.