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klarka
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Homework Statement
g(x) = 1 if x is rational, 0 if x is irrational.
Determine the limit, or prove it doesn't exist.
lim g(x)sinx
x->0
Homework Equations
The Attempt at a Solution
I said the limit is 0.
0 < |g(x)sinx| < |sinx|
lim |g(x)sinx|= 0
x->0
-|sinx| < g(x)sinx < sinx
lim g(x)sinx
x->0
The < are less than or equal. I can't figure out how to put them in correctly.
This was on my final and it's driving me crazy! I couldn't decided if the limit was 0 or didn't exist. If you could point out my mistakes I'd appreciate it!