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bigcookie
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Homework Statement
Vector A⃗ has a magnitude of 20m and makes an angle of 30∘ above the positive x axis. Vector B⃗ has a magnitude of15m and is oriented 60∘ to the left of the y axis.
Find the magnitude of A⃗ −B⃗ .
Find the direction of A⃗ −B⃗ .
Homework Equations
sin 150 = sin 30 = 0.5
cos 150= - cos 30
Angle of direction = tan-1 (y/x)
The Attempt at a Solution
so far
Ax [/B]= 20 cos 30 =17.3 m
Ay = 20 sin 30 = 10 m
Bx = 15cos 150 = -12.99 m
By=15 sin 150 = 7.5 m
add Ax+Bx= 4.31
Ay+By= 17.5
sqrt of [(4.31)^2+(17.5)^2]= 18.0
but i don't know where to go from here ?
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