Find the magnitude of small oscillations

In summary, the conversation discusses a scenario where a bead is tied to a horizontal spring and asked whether it will execute simple harmonic motion (SHM) when displaced. Two methods are presented, with the second method resulting in a non-SHM motion due to the force on the bead being proportional to x^3. The conversation also includes a request for clarification on the solution and a hint on finding the spring force.
  • #1
prabhat rao
15
0

Homework Statement




a rope is tied between 2 walls as shown.a bead of mass 'm' is on the rope as shown. it is constrained to move in the horizontal direction. it is tied to a spring of force constant 'k'- N/m. the spring is initially at its free length 'H'. the bead is displaced by a small displacement 'x' in the horizontal direction. does it execute SHM.If so find the magnitude of small oscillations?
no friction.


the figure is attached!






Homework Equations


T =2 pie/omega


The Attempt at a Solution


Consider the spring to make an angle q with the vertical
The mass in equilibrium in the y direction at all the times
Fsin q = mg
F (h/l)=mg
F = mgl/h
-Fcosq = f_restoring
-Fx/l = f_restoring
-mgl/hl *x =f_restoring
-mgx/h = f_restoring
-mgx/h = ma
ma+mgx.h = 0
a differential equation
omega = sqrt (g/h)
T = 2 pie * sqrt (h/g)
Now the answer is dimensionally correct

method 2

Since the force exerted by the spring is the vectorial sum of the forces along both the directions
F_y/(F_x) = tan q
-F_x= f_restoring = F_y/(tanq)
F_y intially is mg
f_restoring = -mgx/h
so this would be give

T= 2 pie *sqrt (h/g)

An amazing result independent of the spring constant of the force
A spring can only influence the motion along the direction of the spring

Is the solution?? if yes can anybody explain what it means

thank you
 

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  • #2
Hello,

I have a result which shows that the motion is NOT a simple harmonic moiton.
Because the net force on the bead is proportional to [tex]x^3[/tex].
This is just my opinion.


Regards
 
  • #3
Can u please give your method
 
  • #4
An amazing result independent of the spring constant of the force

This is the first sign something is wrong. Looking at your equations, I can't find anything that actually states the force the spring acts on the object (if it's there, it's certainly missing the spring constant
 
  • #5
Is the motion simple harmonic??Please help me
 
  • #6
I'll give you a hint

F_y intially is mg

Wrong! There's a spring pulling on it too
 

FAQ: Find the magnitude of small oscillations

What is the definition of small oscillations?

Small oscillations refer to a type of periodic motion in which the amplitude of the oscillation is significantly smaller than the wavelength of the oscillation. This means that the object is moving back and forth in a relatively small region around its equilibrium position.

How is the magnitude of small oscillations calculated?

The magnitude of small oscillations can be calculated using the equation A = ω²x₀, where A represents the amplitude of the oscillation, ω is the angular frequency, and x₀ is the initial displacement from the equilibrium position.

What factors affect the magnitude of small oscillations?

The magnitude of small oscillations is affected by the mass and stiffness of the oscillating object. Objects with larger masses or higher stiffness will have a greater magnitude of oscillation.

What is the significance of finding the magnitude of small oscillations?

Knowing the magnitude of small oscillations can help predict the behavior of a system and determine its stability. It can also be used to calculate other important parameters such as the period and frequency of the oscillations.

How is the magnitude of small oscillations related to the amplitude of the oscillation?

The magnitude of small oscillations and the amplitude of the oscillation are directly proportional. This means that as the magnitude of small oscillations increases, so does the amplitude of the oscillation, and vice versa.

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