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prishila
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Homework Statement
A nickel pole is put in an AgNO3 solution with volume 50ml and concentration 0.1 mol/litre until the concrentration is 0.02 mole/litre. Find the mass of Ag that is put around the Nickel pole.
Homework Equations
2AgNo3+Ni->Ni(NO3)2+2Ag
number of moles= concrentration*volume
n1=0.1*0.05=0.005 moles
n2=0.02*0.05=0.001 moles.
n1-n2=0.004 moles.
So the numebr of Ag moles will be 0.004 too
The Attempt at a Solution
n1=0.1*0.05=0.005 moles
n2=0.02*0.05=0.001 moles.
n1-n2=0.004 moles.
So the number of Ag moles will be 0.004 too
Then m=0.004*108=0.432 moles. Am I right?