- #1
kidia
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Using the formula relating the tangent of angle p enclosed between two given straight line L1 and L2 and respective slope m1 and m2,Find the measure in degrees of angles A and C of the triangle with vertices A(-3,4),B(5,6) and C(2,1)
My work is
Tan A = Ma = yb-ya/xb-xa=6-4/5+3=2/8=1/4
Tan A =1/4
Tan C = Mb = yb-yc/xb-xc=5/3
Tan C = 5/3
So Angle A = arctan 1/4
Angle C = arctan 5/3
Any idea on this?
My work is
Tan A = Ma = yb-ya/xb-xa=6-4/5+3=2/8=1/4
Tan A =1/4
Tan C = Mb = yb-yc/xb-xc=5/3
Tan C = 5/3
So Angle A = arctan 1/4
Angle C = arctan 5/3
Any idea on this?