Find the Molar Mass of A: A + B + Energy = C | 35.5g A, 750kJ Heat Released

  • Thread starter Speedking96
  • Start date
  • Tags
    Mass
In summary, the given equation shows a reaction between molecules A, B, and C, with a heat release of 1000 kJ for every 2 moles of A. The problem involves finding the molar mass of A when 35.5 g of A is used with enough B and 750 kJ of energy. Using the given information, the number of moles of A used is 1.5, and the molar mass of A is calculated to be 23.7 g/mol. However, the question is unclear about whether there was enough heat to react all of A.
  • #1
Speedking96
104
0

Homework Statement



2 A + 3 B + 1000 kJ ==> 4 C

where A,B,C are molecules. A mass of 35.5 g of A is used with the right quantity of B, and the mixture of reactants is heated with an energy of 750 kJ. Find the molar mass of A.

2. The attempt at a solution

Heat released per mole in terms of "A" : 1000 kJ / 2 = 500 kJ/mole "A"

Finding number of moles used:

(750 kJ) / (500 kJ/mole) = 1.5 mol "A"

Molar mass = (35.5 grams) / (1.5 mol) = 23.7 g/mol
 
Physics news on Phys.org
  • #2
Your approach looks OK, but the question is poorly worded - it doesn't say anything about whether there was enough heat to react all of A.
 

FAQ: Find the Molar Mass of A: A + B + Energy = C | 35.5g A, 750kJ Heat Released

What is molar mass?

Molar mass is the mass of a substance in grams per mole. It is also known as molecular weight or formula weight.

Why is molar mass important?

Molar mass is important because it helps in determining the amount of a substance in moles. It is also used in calculations to convert between mass, moles, and number of particles.

How is molar mass calculated?

Molar mass is calculated by adding the atomic masses of all the atoms in a chemical formula. The atomic masses can be found on the periodic table of elements.

What is the unit of molar mass?

The unit of molar mass is grams per mole (g/mol).

How is molar mass used in chemistry?

Molar mass is used in various calculations in chemistry, such as determining the amount of reactants needed for a reaction, calculating the concentration of a solution, and determining the molecular formula of a compound.

Similar threads

Replies
6
Views
2K
Replies
5
Views
2K
Replies
5
Views
2K
Replies
1
Views
2K
Replies
14
Views
9K
Back
Top