Find the particular solution of the second order differential equation

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In summary, to find the particular solution of a second-order differential equation, one typically identifies the homogeneous solution and then uses methods such as undetermined coefficients or variation of parameters to determine the particular solution that satisfies the non-homogeneous part of the equation. This involves analyzing the form of the non-homogeneous term and applying appropriate techniques to derive the specific solution that complements the general solution of the homogeneous equation.
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chwala
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Homework Statement
see attached
Relevant Equations
understanding of homogenous and inhomegenous approach in solving ode's
My interest is on the highlighted (In Red). Otherwise the other steps are clear.

1712993429550.png



1712993460897.png


We have on that part of the problem,

##(-p\sin t -q\cos t)-12(p\cos t -q \sin t)+36p\sin t +36q\cos t = 37 \sin t + 0 \cos t##

Ah I just realized we are solving a simultaneous equation for ##p## and ##q## !

My problem was on how to get,

##-q-12p+36q =0##

Clear now.

Cheers if there is another approach to the problem. Laplace? I may need to refresh on it.

I now have (using laplace);

##s^2 \bar y -12(s\bar y -1) +36 \bar y = \dfrac {37}{s^2+1}##

##\bar y = \dfrac{37}{(s^2+1)(s-6)^2} - \dfrac{12}{(s-6)^2}## will proceed later.
 
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  • #2
chwala said:
Ah I just realized we are solving a simultaneous equation for p and q !
Hope you figured it out.
The idea is that a particular solution will be ##x_p = A\sin(t) + B\cos(t)##
When you substitute the above into x'' - 12x' + 36x you'll have some combination of sine and cosine terms that must be identically equal to ##37\sin(t)##. Since there is no cosine term, its coefficient must be zero. This will allow you to determine A and B.
 
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  • #3
chwala said:
Homework Statement: see attached
Relevant Equations: understanding of homogenous and inhomegenous approach in solving ode's

My interest is on the highlighted (In Red). Otherwise the other steps are clear.

View attachment 343289


View attachment 343290

We have on that part of the problem,

##(-p\sin t -q\cos t)-12(p\cos t -q \sin t)+36p\sin t +36q\cos t = 37 \sin t + 0 \cos t##

Ah I just realized we are solving a simultaneous equation for ##p## and ##q## !

My problem was on how to get,

##-q-12p+36q =0##

Clear now.

Cheers if there is another approach to the problem. Laplace? I may need to refresh on it.

I now have (using laplace);

##s^2 \bar y -12(s\bar y -1) +36 \bar y = \dfrac {37}{s^2+1}##

##\bar y = \dfrac{37}{(s^2+1)(s-6)^2} - \dfrac{12}{(s-6)^2}## will proceed later.
I asked chat gpt to use laplace transform into realising a solution. It is interesting that chat gpt is able to give the steps to a solution... But it is not able to solve the definite integral i.e

##x(t)= 37\int_0^t (ue^{6u})\sin (t-u) du##

Finally, it has indeed solved the problem using laplace transforms (see attached)...let me counter check its steps. Cheers.
 

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  • #4
chwala said:
I asked chat gpt to use laplace transform into realising a solution. It is interesting that chat gpt is able to give the steps to a solution... But it is not able to solve the definite integral i.e
As you should know, AI chatbots are not allowed as references in PF technical threads. This thread is now closed.
 
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FAQ: Find the particular solution of the second order differential equation

What is a second order differential equation?

A second order differential equation is an equation that involves the second derivative of a function. It can be expressed in the general form: \( a(x)y'' + b(x)y' + c(x)y = f(x) \), where \( y \) is the unknown function, \( y' \) is its first derivative, \( y'' \) is its second derivative, and \( a(x), b(x), c(x), \) and \( f(x) \) are given functions of \( x \).

What is a particular solution?

A particular solution of a differential equation is a specific solution that satisfies both the differential equation and any initial or boundary conditions provided. It is one of the solutions that can be derived from the general solution, which includes arbitrary constants.

How do you find the particular solution of a second order differential equation?

To find the particular solution, you generally follow these steps: 1. Solve the associated homogeneous equation to find the complementary solution.2. Use an appropriate method (such as undetermined coefficients or variation of parameters) to find a particular solution that fits the non-homogeneous part of the equation.3. Combine the complementary solution and the particular solution to form the general solution.

What methods can be used to find a particular solution?

Common methods for finding a particular solution include:1. Method of Undetermined Coefficients: This method is used when the non-homogeneous term is a polynomial, exponential, sine, or cosine function.2. Variation of Parameters: This method is more general and can be used for any non-homogeneous term by assuming the particular solution has a form that allows for the coefficients to vary.3. Laplace Transforms: This method transforms the differential equation into an algebraic equation, which can be solved more easily.

What role do initial or boundary conditions play in finding a particular solution?

Initial or boundary conditions are crucial as they specify the unique solution of the differential equation from the general solution. They allow you to determine the values of the arbitrary constants present in the general solution, leading to the specific particular solution that meets the given conditions.

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