Yes, good point. I find quite a lot of missteps in threads on this forum come from applying a memorised equation out of its rather narrow context. As a student, I had the advantage of not being able to remember reams of equations, so relied on the most fundamental ones.kuruman said:Yes, strictly in the context of the question. To the untrained eye, the equation ##T=2\pi\sqrt{d/g}## may seem to imply that when the oscillator is taken to the Moon, the period will decrease, just like the period of a pendulum.
it's weird.. why there's g on periode and not depend on g..haruspex said:Yes, good point. I find quite a lot of missteps in threads on this forum come from applying a memorised equation out of its rather narrow context. As a student, I had the advantage of not being able to remember reams of equations, so relied on the most fundamental ones.
haha.. Socrates ;)kuruman said:Because when ##g## decreases by some factor, ##d = mg/k## decreases by the same factor the ratio ##d/g## remains the same because it's equal to the ratio ##m/k## that remains the same.