- #1
AdnamaLeigh
- 42
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A 10.7kg cylinder rolls without slipping on a rough surface. At the instant when its center of gravity has a speed of 11.8 m/s,
a) Find the translational kinetic energy of its center of gravity.
b) Find the rotational kinetic energy about its center of mass at that time.
c) What is its kinetic energy?
I already found the answer to a by using the formula Ke = .5mv^2 and it's 744.934 J. For b I want to use the rotational kinetic energy formula Ke = .5Iω^2, but I need inertia for that. I can't find the inertia without the radius. Besides, I wouldn't know what formula to use since they don't explicitly say whether or not the cylinder is hollow.
a) Find the translational kinetic energy of its center of gravity.
b) Find the rotational kinetic energy about its center of mass at that time.
c) What is its kinetic energy?
I already found the answer to a by using the formula Ke = .5mv^2 and it's 744.934 J. For b I want to use the rotational kinetic energy formula Ke = .5Iω^2, but I need inertia for that. I can't find the inertia without the radius. Besides, I wouldn't know what formula to use since they don't explicitly say whether or not the cylinder is hollow.