- #1
FrostScYthe
- 80
- 0
The general equation for a plane is ax + by + cz = k, where a, b, c, k are constants, and the plane is satisfied by points (x,y,z). If a specific plane contains both points (2, 1, 3) and (2, 1, 5), what is the value of c?
The answer is supposed to be c = 0, but I don't know how to get there.
I tried this [(2, 1, 3)-(2, 1, 5)]t + (2, 1, 5) so I get
x = 2
y = 1
z = 5 - 2t
but I don't know what to do from there
The answer is supposed to be c = 0, but I don't know how to get there.
I tried this [(2, 1, 3)-(2, 1, 5)]t + (2, 1, 5) so I get
x = 2
y = 1
z = 5 - 2t
but I don't know what to do from there