Find the volume of parallelopiped

  • Thread starter utkarshakash
  • Start date
  • Tags
    Volume
In summary, the homework statement says that if a,b, and c are the vectors that represent the three edges of a paralleopiped, then the volume is 4∏/3 cos theta.
  • #1
utkarshakash
Gold Member
854
13

Homework Statement


Let a,b and c are the three vectors such that |a|=|b|=|c| =2 and angle between a and b is ∏/3, b and c is ∏/3 and a and c is ∏/3
If a,b and c represents adjacent edges of paralleopiped then find its volume.

Homework Equations



The Attempt at a Solution



Volume of parallelopied = [itex] \left( \vec{a} \times \vec{b} \right) . \vec{c} \\
|\vec{a} \times \vec{b}| |\vec{c}| cos \theta \\
4 \sqrt{3} cos \theta [/itex]

But I don't know what is the angle between a x b and c.
 
Physics news on Phys.org
  • #2
You could approach it as a geometry question (have you worked out what shape the origin and the endpoints of the three vectors give you?). It's not obvious to me how to solve it with a purely vectorial approach.
 
  • #3
haruspex said:
You could approach it as a geometry question (have you worked out what shape the origin and the endpoints of the three vectors give you?). It's not obvious to me how to solve it with a purely vectorial approach.

Since it is a parallelopiped it is obvious that the given vectors are non-coplanar and the angle between each of them is ∏/3. If we consider only the origin and endpoints it will look like a tetrahedron.
 
  • #4
utkarshakash said:
Since it is a parallelopiped it is obvious that the given vectors are non-coplanar and the angle between each of them is ∏/3. If we consider only the origin and endpoints it will look like a tetrahedron.

Are you sure that those vectors are not not coplanar? :devil:

The three side-edges of the tetrahedron are of the same length and each pair enclose the same angle. You project the tetrahedron onto the plane of the base. What angle do the pairs of edges enclose in the projection?

ehild
 
  • #5
utkarshakash said:
Since it is a parallelopiped it is obvious that the given vectors are non-coplanar and the angle between each of them is ∏/3. If we consider only the origin and endpoints it will look like a tetrahedron.

Right, so courtesy of Pythagoras you can figure out the height. From there you can compute the volume directly, or out of interest relate it to the angle between axb and c.
 
  • Like
Likes 1 person

FAQ: Find the volume of parallelopiped

1. What is a parallelopiped?

A parallelopiped is a three-dimensional figure with six faces, each of which is a parallelogram. It is similar to a rectangular prism, but its faces are not necessarily rectangles.

2. How do I find the volume of a parallelopiped?

To find the volume of a parallelopiped, you can use the formula V = l * w * h, where l is the length, w is the width, and h is the height of the parallelopiped. Simply plug in the values for each measurement and multiply them together to find the volume.

3. Can I use the same formula to find the volume of any parallelopiped?

Yes, the formula V = l * w * h can be used to find the volume of any parallelopiped, regardless of its dimensions. Just make sure to correctly label and measure each side before plugging them into the formula.

4. What units should I use for the measurements when finding the volume?

The units used for the measurements (length, width, and height) should all be the same. For example, if the length is measured in inches, the width and height should also be measured in inches. This will ensure that the volume is also measured in cubic units, such as cubic inches or cubic feet.

5. Can I find the volume of a parallelopiped if I only know the area of its base and its height?

Yes, if you know the area of the base and the height of the parallelopiped, you can use the formula V = A * h, where A is the area of the base and h is the height. This formula works for any parallelopiped with a rectangular base, such as a cube or rectangular prism.

Back
Top