- #1
Color_of_Cyan
- 386
- 0
Homework Statement
Apply source transformation to find the Thevenin equivalent circuit
Homework Equations
voltage division, source transformation
The Attempt at a Solution
Simplify the far left current source to get
Then Vth of this = (50V + 20V)*(100/200)
= 35V
and Rth of it = 100||100 = 50Ω
so now:Then Vth of this = (35V - 10V)*(100/150)
= 16.6667V
Rth of it = 50||100 = 33.333Ωso finally this:
And then the final Vth I got
= 16.6667*(100/133.3333)
VTh = 12.5V
but from the given solution from my professor the answer is really 10V for the Thevenin voltage and she did the whole problem differently by instead making everything Norton equivalent instead (changing voltage sources to current sources and moving the resistors in front to parallel them instead). Shouldn't the answer still be the same though or did I just make a mistake somewhere?
I got the same RTh though which is
33.333||100 = 25Ω
RTh = 25Ω
Last edited by a moderator: