- #1
DeanBH
- 82
- 0
so i have y = 1/sqroot(3x+2)
find volume when rotated around x, regions are x=2 and x=0
equation needed: V= integral Pi*y^2*dx
so.
i do intergral pi* (1/sqroot(3x+2))^2 * dx
so i get pi integral 1/(3x+2) dx
so how do i integrate 1/sqroot(3x+2) ?
can someone take me though it , because i know there's meant to be a constant near the ln, but i don't know how to find it.
thanks, sorry if it's explained bad
find volume when rotated around x, regions are x=2 and x=0
equation needed: V= integral Pi*y^2*dx
so.
i do intergral pi* (1/sqroot(3x+2))^2 * dx
so i get pi integral 1/(3x+2) dx
so how do i integrate 1/sqroot(3x+2) ?
can someone take me though it , because i know there's meant to be a constant near the ln, but i don't know how to find it.
thanks, sorry if it's explained bad