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Homework Statement
The density of solid gold at 20°C is
ρ = 19.3 g/cm3.
When it is liquid at 1064°C the density of the liquid state is decreased: 17.3 g/cm3. How much work does a block of gold of mass 407 kg do if it is heated at
p = 1.0 atm
from 20°C to 1064°C?
Homework Equations
density=mass/volume
PV=nRT
W=-pdeltaV
The Attempt at a Solution
I started by taking difference between two pressures =2.0g/cm3 and then converted that to 2000kg/cm3. with this i used
p=m/v
v=m/p
v=407kg/2000kg/m3
v=0.2035m3 =203.5L
W=-pdeltaV
W=1.0atm(203.5L)
W= 203.5atm.L=20619 J
this does not seem correct at all and it isn't.