- #1
owlman76
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1. Homework Statement
An Ideal gas and a block of copper have equal volumes V and at the same temperature T and atmosphere pressure P. The pressure on both substances is increased reversibly and isothermally to 5P.
a) Find the work done on the ideal gas if V = 0.5 m and T= 300 K P = 1.01*10^5 Pa
b) Find the work done on the copper using the definition of compressibility k= 0.7*10^-6. for copper
2. Homework Equations
PV=nRT
W= PdV
dW=PVBdT - PVkDP
3. The Attempt at a Solution
Part A) P1V1=P2V2=nRT SO W = PdV SO W = nRT/V dV SO W= P1V1 * ln(.1/.5) = -81276.6 Joules
I have no idea if that is correct
Part B) dW=PVBdT - PVkDP
Temp is constant so first part drops out so
dW = -PVkdP
My answer was W=-42844 Joules
Any help on solving these equations is awesome... I don't know if I got either part right or even close to. THANK YOU
An Ideal gas and a block of copper have equal volumes V and at the same temperature T and atmosphere pressure P. The pressure on both substances is increased reversibly and isothermally to 5P.
a) Find the work done on the ideal gas if V = 0.5 m and T= 300 K P = 1.01*10^5 Pa
b) Find the work done on the copper using the definition of compressibility k= 0.7*10^-6. for copper
2. Homework Equations
PV=nRT
W= PdV
dW=PVBdT - PVkDP
3. The Attempt at a Solution
Part A) P1V1=P2V2=nRT SO W = PdV SO W = nRT/V dV SO W= P1V1 * ln(.1/.5) = -81276.6 Joules
I have no idea if that is correct
Part B) dW=PVBdT - PVkDP
Temp is constant so first part drops out so
dW = -PVkdP
My answer was W=-42844 Joules
Any help on solving these equations is awesome... I don't know if I got either part right or even close to. THANK YOU