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shanepitts
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Homework Statement
Homework Equations
∫F⋅dr=W
If r2 = x2 + y2 + z2, then what is dr? In general, dr ≠ dx + dy + dzshanepitts said:Homework Statement
View attachment 89256
Homework Equations
∫F⋅dr=W
The Attempt at a Solution
View attachment 89257
shanepitts said:Thank you,
But how can I calculate the work down on each leg of the triangle?
Shall I integrate ∫C F⋅dr along each line, using the limits as the length of each leg, and then sum them up?
Work in two dimensions is defined as the product of the magnitude of the force and the displacement in the direction of the force. It is a scalar quantity measured in joules (J).
The formula for calculating work in two dimensions is W = F * d * cosθ, where W is work, F is the force applied, d is the displacement, and θ is the angle between the force and displacement vectors.
The angle between the force and displacement vectors represents the amount of work that is being done in the direction of the force. A greater angle means that less work is being done, while a smaller angle means that more work is being done.
Yes, negative work is possible in two dimensions. Negative work occurs when the force and displacement vectors are in opposite directions, meaning that the force is working against the displacement. This results in a negative value for work.
The direction of work in two dimensions can be determined by looking at the angle between the force and displacement vectors. If the angle is less than 90 degrees, the work is positive and in the direction of the force. If the angle is greater than 90 degrees, the work is negative and in the opposite direction of the force.