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DeltaT37
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Homework Statement
This problem comes from a practice test that I am reviewing before my final. My main confusion comes from the mathematical implication of the integral being an extremum. The first two parameters are y(x=0) = 0 and y(x = π/2) = 1. The third says the integral from 0 to 1 of ∫[ (dy/dx)2 - y2 ]dx is an extremum.
Homework Equations
N/A
The Attempt at a Solution
Clearly, the first two parameters are easily solved by y = sin(x). However, this third bit of information is very confusing to me. I first considered, in 1 dimension the first derivative of a function at an extremum is zero, and thus perhaps plugging in zero for dy/dx. That didn't seem right so I attempted to solve the integral, but couldn't figure out the first part to solve. Thirdly, I tried plugging in sin(x) and see what could be achieved, with a final result of something like .5-.27 = extremum (integral of sin2(x) from zero to one is the .27.) If possible, the guidance I am looking for is how to think about mathematically the fact that the the integrand, involving dy/dx is related to the extremum.
Thanks. Sorry if the formatting is off, first post here.