Finding a Slope of Any Linear Function Without Using (x2-x1; y2-y1)

In summary, a linear function can be written as y = ax + b and the slope of the tangent line at any point on the curve can be found by evaluating the derivative of the function at that point.
  • #1
naoufelabs
17
0
Hi everyone,

Please I have a problem to find a slope (Tangent line) of any linear function without using (x2-x1; y2-y1).
What I want is a function that can be applied in any position of any type of function, example: x2, 3x3+sin(x), ln(x)+x3, and so one. (Like as in this web page "Java Applet" : http://www.math.brown.edu/help/tangentline.html )

Thank you.
 
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  • #2
naoufelabs said:
Hi everyone,

Please I have a problem to find a slope (Tangent line) of any linear function without using (x2-x1; y2-y1).
What I want is a function that can be applied in any position of any type of function, example: x2, 3x3+sin(x), ln(x)+x3, and so one. (Like as in this web page "Java Applet" : http://www.math.brown.edu/help/tangentline.html )

Thank you.

Is this a homework problem?

What you are asking is unclear. A linear function is one with the form f(x) = ax + b. This function's graph is a straight line with slope a.

For other functions, such as the ones you mentioned, the slope of the tangent line at a point on the curve, is given by the derivative of the function, evaluated at the x value at the point in question.

So are you asking about linear functions or functions in general?
 
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  • #3
I ask about linear function.
 
  • #4
Any linear function of x can be written as y= ax+ b for some numbers a and b. The slope is the number a.
 
  • #5
Thanks
 

FAQ: Finding a Slope of Any Linear Function Without Using (x2-x1; y2-y1)

What is the formula for finding the slope of a linear function without using (x2-x1; y2-y1)?

The formula for finding the slope of a linear function without using (x2-x1; y2-y1) is simply rise over run, which is represented as (y2-y1)/(x2-x1).

How is the slope of a linear function calculated using the rise over run method?

The slope of a linear function can be calculated using the rise over run method by identifying two points on the line and finding the difference in y-coordinates (rise) and the difference in x-coordinates (run), and then dividing the rise by the run.

Can you give an example of finding the slope of a linear function using the rise over run method?

For example, if we have the points (2,4) and (6,8), we can find the slope by subtracting 4 from 8 to get a rise of 4, and subtracting 2 from 6 to get a run of 4. Therefore, the slope of this line is 4/4, which simplifies to 1.

Why is it important to know how to find the slope of a linear function without using (x2-x1; y2-y1)?

Knowing how to find the slope of a linear function without using (x2-x1; y2-y1) allows us to find the slope of a line without needing to know the specific coordinates of two points. This can be useful when working with equations of lines or solving real-life problems involving slope.

Are there any other methods for finding the slope of a linear function?

Yes, there are other methods for finding the slope of a linear function, such as using the slope-intercept form of a line (y=mx+b) or the point-slope form of a line (y-y1=m(x-x1)). However, the rise over run method is a simple and efficient way to calculate the slope without needing to rearrange equations or use specific points.

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