- #1
climbon
- 18
- 0
Hi, I have this equation to solve.
y'' + (1/x)y' + [(x^2) + k + (m^2 / x^2)]y = 0
now, I've tried to solve this using frobenius method but cannot formulate a solution.
I have that
a_(n+4) = [-ka_(n+2) - a_(n)] / [n^2 +/- 2inm]
is my recurrence relation, but now I'm stuck and don't know how to proceed, any help greatly appreciated.
thanks.
y'' + (1/x)y' + [(x^2) + k + (m^2 / x^2)]y = 0
now, I've tried to solve this using frobenius method but cannot formulate a solution.
I have that
a_(n+4) = [-ka_(n+2) - a_(n)] / [n^2 +/- 2inm]
is my recurrence relation, but now I'm stuck and don't know how to proceed, any help greatly appreciated.
thanks.