- #1
santoki
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Homework Statement
Two masses are suspended from a pulley:
[PLAIN]http://i.imgur.com/B4x8pzx.png[/PLAIN]
mass of pulley = 0.20kg
radius = 0.15m
constant torque = 0.35Nm due to friction between the rotating pulley and its axle
m1 = 0.40kg
m2 = 0.80kg
What is the acceleration of the suspended masses?
Homework Equations
Fnet = I[itex]\alpha[/itex]
The Attempt at a Solution
I tried to make sense out of this problem using the equation from above initially, but my acceleration was way too big. I know the acceleration is supposed to be somewhat big anyway but it was too big. So instead I searched for helm on google first and found an equation which told me to do this:
I = (1/2)mr2 = (1/2)(0.20)(0.5)2 - 0.025kgm2
a = [g(m1 - m2) - [itex]\tau[/itex]/r]/(m1 + m2 + I/r2)
a = 9.8(0.80+0.40)-(0.35/0.15)/(0.80+0.40+(0.0025/(0.15)2)
a = 1.23 m/s2
If this is right, how can I clean it up to make it relevant to how Fnet = I[itex]\alpha[/itex] is supposed to be set up?