Finding all tangent lines through a point

In summary, the problem asks for finding all tangent lines of the graph f(x)=x+3/x that have a y intercept of 4. Using the derivative of f(x), the slope of the tangent line is found to be (a+3/a-4)/(a-0), where a is the x-coordinate of the point of tangency. After solving for a, it is found that a=3/2. However, upon further examination of the graph, it is observed that there are no points x<0 where the tangent line would go through (0,4). Therefore, there is only one point of tangency that satisfies the given conditions.
  • #1
hlin818
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Homework Statement



Find all tangent lines of the graph f(x)=x+3/x that have a y intercept of 4.

Homework Equations





The Attempt at a Solution



Assume a is the x coordinate of a point of tangency. Thus the point of tangency is (a, a+3/a). We know the tangent line must pass through (0,4) so the slope of the line must be (a+3/a-4)/(a-0).

f'(x)=1-3/(x^2)

Derivative of f at point a must equal the slope of the tangent line, i.e. we must have
f'(a)=1-3/(a^2)=(a+3/a-4)/(a-0)=m

Solving I get a=3/2. However, looking at the graph of f(x), it seems there should be two points where the tangent line passes through 4, the other one being on the part of the f(x) where x<0. Where did I go wrong?
 
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  • #2
hlin818 said:

Homework Statement



Find all tangent lines of the graph f(x)=x+3/x that have a y intercept of 4.

Homework Equations





The Attempt at a Solution



Assume a is the x coordinate of a point of tangency. Thus the point of tangency is (a, a+3/a). We know the tangent line must pass through (0,4) so the slope of the line must be (a+3/a-4)/(a-0).

f'(x)=1-3/(x^2)

Derivative of f at point a must equal the slope of the tangent line, i.e. we must have
f'(a)=1-3/(a^2)=(a+3/a-4)/(a-0)=m

Solving I get a=3/2. However, looking at the graph of f(x), it seems there should be two points where the tangent line passes through 4, the other one being on the part of the f(x) where x<0. Where did I go wrong?

I don't think you went wrong anywhere. Looking at the graph I don't see any points x<0 where the tangent line will go through (0,4).
 
  • #3
If a is negative, the y intercepts of the tangent lines are also negative.

ehild
 

FAQ: Finding all tangent lines through a point

What does it mean to find all tangent lines through a point?

When finding all tangent lines through a point, it means to determine all the possible lines that touch a given curve at a specific point and have the same slope as the curve at that point.

How do you find all tangent lines through a point?

To find all tangent lines through a point, you must first find the derivative of the curve at that point. Then, using the point-slope formula, you can find the equation of the tangent line. This process is repeated for all possible values of the derivative.

What is the purpose of finding all tangent lines through a point?

The purpose of finding all tangent lines through a point is to better understand the behavior of a curve at a specific point. It can also be used to solve problems involving optimization or finding maximum and minimum values of a function.

Are there any limitations to finding all tangent lines through a point?

Yes, there are limitations to finding all tangent lines through a point. This method only works for differentiable functions, and the number of tangent lines is limited to the number of distinct values of the derivative at the given point.

Can finding all tangent lines through a point help with curve sketching?

Yes, finding all tangent lines through a point can be useful in curve sketching. Knowing the slope and equations of the tangent lines can help determine the behavior of the curve at that point and assist in creating an accurate sketch of the curve.

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