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mlostrac
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Homework Statement
When connected in series to a 110-V line, two resistors use one-fourth the power
that is used when they are connected in parallel. If one resistor is
2.0 kΩ, what is the resistance of the other?
Homework Equations
1/Rt = 1/R1 +1/R2 (total resistance in parallel)
Rt = R1 + R2 (resistance in series)
Power = Current x Voltage
The Attempt at a Solution
So far my attempts have fizzled, ending with negative numbers.
Heres what I did:
1) Set the two hypothetical circuits (series and parallel) equal to each other by isolating the power:
P1 = 110^2/0.25(R1+R2)
P2 = 110^2(R1+R2)
And then isolating for R2 and solving (since we have R1 = 2000 ohms)
I ended up doing the quadratic equation and getting two negative numbers...
Any help would be appreciated :)