Finding B^-1 in 3x3 Matrices with Linear Algebra

In summary, we are given that $ABC=I$, $|3A|=81$, and $|C^T|=2$. We are asked to find $|B^{-1}|$. Using the properties of the determinant, we know that $|A|=27$ and $|C|=2$, but we cannot determine $|B|$ from the given information. Therefore, we cannot find $|B^{-1}|$.
  • #1
mahmoud shaaban
4
0
if A and B are 3x3 matrices such that: ABC = I, |3A|=81 and |C^T|= 2 , how to find |B^-1|

I couldn't solve this because there is not much given.
 
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  • #2
mahmoud shaaban said:
if A and B are 3x3 matrices such that: ABC = I, |3A|=81 and |C^T|= 2 , how to find |B^-1|

I couldn't solve this because there is not much given.

Hi mahmoud shaaban!

We are given:
$$ABC=I \Rightarrow
|ABC|=|I| \Rightarrow
|A||B||C|=1
$$
Can we find $|A|$ and $|C|$? (Wondering)
 
  • #3
I know that A = 27 ,but how can i know what C = ?? if the given is C^T
 
  • #4
mahmoud shaaban said:
I know that A = 27 ,but how can i know what C = ?? if the given is C^T

Properties of the determinant are that:
$$|xA|=x^n|A| \\
|C^T|=|C| \\
|B^{-1}|=\frac{1}{|B|}$$

Oh, that also means that $|3A|=3^3|A|=27|A|=81$. (Thinking)
 

FAQ: Finding B^-1 in 3x3 Matrices with Linear Algebra

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