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- Homework Statement
- A free electron initially moves along the positive x-axis direction with the de Broglie wavelength of 0.20 nm. If this election is further accelerated by 100 eV along the positive x-axis direction, what is the de Broglie wavelength of the electron after the acceleration?
- Relevant Equations
- λ=h/p
KE = 1/2mv^2
KE = 100eV x (1.6x10^-19)
v(new) = √(2KE/9.1×10^-31 )
= 5.9x10^6m/sv(original) = h/λm
= 6.6x10^-34 / (0.2x10^-9 x 9.1x10^-31)
= 3.64x10^6m/s
v(new) = √(2KE/9.1×10^-31 )
= 5.9x10^6m/sv(original) = h/λm
= 6.6x10^-34 / (0.2x10^-9 x 9.1x10^-31)
= 3.64x10^6m/s
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