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Ly444999
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Homework Statement
A 26.2 kg child rides a 1.00 kg potato sack down a 2.05 m high slide. If the child starts from rest and has a speed of 1.60 m/s at the bottom of the slide, what is the change in thermal energy of the child on their potato sack and the slide?
Homework Equations
KE = (1/2)mv2
PE = mgh
The Attempt at a Solution
PE = KE + Eth
mgh = (1/2)mv2+Eth
(27.2 kg)*(9.8 m/s2)*(2.05 m) = (1/2)*(27.2 kg)*(1.60 m/s)+Eth
Eth= 511.632 J
Was I supposed to add the mass of the child and potato sack together? Also was my answer, 511.632 J, correct or is there more I have to do to find the change in thermal energy? or is this whole approach wrong?
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