- #1
imminentfate
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Hi there :)
At 19[tex]\circ[/tex]C, a rod is exactly 20.08 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 285[tex]\circ[/tex]C, where the rod now measures 20.18 cm on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?
I used the formula for linear expansion
change in L = Lx(coefficient of linear expansion)(change in temperature)
My attempt:
Steel's coefficient of linear expansion as given by my textbook: 11x10-6
So over the temperature range of 266 degrees (285 - 19), each centimetre would differ by about (266)(11x10-6) = 0.002926
Multiplying by 20.18 gives 0.059
Taking this away from 20.18 gives: 20.1209
The change in length will now be: 20.12 - 20.08 = 0.04095
Subbing into the expansion formula:
0.04095 = (20.08)(285 - 19)(a)
a = 7.667x10-6
This is for an assignment, and I just want to see if I'm heading in the right direction
Thanks in advance
At 19[tex]\circ[/tex]C, a rod is exactly 20.08 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 285[tex]\circ[/tex]C, where the rod now measures 20.18 cm on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?
I used the formula for linear expansion
change in L = Lx(coefficient of linear expansion)(change in temperature)
My attempt:
Steel's coefficient of linear expansion as given by my textbook: 11x10-6
So over the temperature range of 266 degrees (285 - 19), each centimetre would differ by about (266)(11x10-6) = 0.002926
Multiplying by 20.18 gives 0.059
Taking this away from 20.18 gives: 20.1209
The change in length will now be: 20.12 - 20.08 = 0.04095
Subbing into the expansion formula:
0.04095 = (20.08)(285 - 19)(a)
a = 7.667x10-6
This is for an assignment, and I just want to see if I'm heading in the right direction
Thanks in advance
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