Finding Complete Orthogonal Systems for Boundary Value Problems

In summary, the conversation discusses finding a complete orthogonal system of a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ with boundary conditions of $f(0)=f(\pi)=0$. The suggestion is to use a Fourier Series and find the coefficients, with the remaining orthogonal system consisting of the functions $\sin(kx)$ where $k \in \mathbb{Z}_{>0}$. This only works for an initial value problem, and the complete orthogonal system will consist of the functions $1$, $\sin(kx)$, and $\cos(kx)$ that remain after applying the boundary conditions.
  • #1
evinda
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Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)
 
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  • #2
evinda said:
Hello! (Wave)

Suppose that we have a $C^{\infty}$ function $f: [0, \pi] \to \mathbb{R}$ for which it holds that $f(0)=f(\pi)=0$.

How can we find a complete orthogonal system of this space? (Thinking)

Hey! (Smile)

Have you considered a Fourier Series? (Wondering)
 
  • #3
I like Serena said:
Hey! (Smile)

Have you considered a Fourier Series? (Wondering)

So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)
 
  • #4
evinda said:
So do we find the coefficients of the Fourier series

$$f \sim \frac{a_0}{2}+ \sum_{k=1}^{\infty} ( a_k \cos(kx)+ b_k \sin(kx)) $$

and from this we find an orthogonal system? How can we do it? (Thinking)

First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)
 
  • #5
I like Serena said:
First off, we know that the Fourier series is an orthogonal system. (Nerd)

Since each function in the system must fit the boundary conditions, it follows that $a_k=0$.
So we're left with:
$$f(x) = \sum_{k=1}^{\infty} b_k \sin(kx)$$
(Thinking)

That is, the orthogonal system is:
$$\{ x \mapsto \sin(kx) \mid k \in \mathbb Z_{>0} \}$$
(Mmm)

So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)
 
  • #6
evinda said:
So the complete orthogonal system is the set of the eigenfunctions, right? (Thinking)

Which eigenfunctions? :confused:
 
  • #7
I like Serena said:
Which eigenfunctions? :confused:

Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)
 
  • #8
evinda said:
Oh, this holds only if we are given an initial value problem, right? (Thinking)

So if we are given a function and boundary conditions, do we find the Fourier series of the function and apply the boundary conditions and the orthogonal complete system will consist of the functions $1$ / $\sin kx$ / $\cos kx$ that will remain? (Thinking)

Basically, yes. (Smile)
 

FAQ: Finding Complete Orthogonal Systems for Boundary Value Problems

What is a complete orthogonal system?

A complete orthogonal system is a set of vectors that are mutually perpendicular (orthogonal) and span the entire vector space. This means that any vector in the space can be expressed as a linear combination of these vectors.

How is a complete orthogonal system useful in mathematics?

In mathematics, a complete orthogonal system is useful for simplifying calculations and solving problems involving vectors. It allows for easier manipulation of vectors and can be used to find solutions to systems of linear equations.

Can a complete orthogonal system be non-orthogonal?

No, a complete orthogonal system must be orthogonal by definition. If any of the vectors in the system are not perpendicular to each other, then the system is not considered complete.

What is the difference between a complete orthogonal system and an orthonormal system?

The main difference between a complete orthogonal system and an orthonormal system is that in an orthonormal system, the vectors are not only orthogonal but also have a magnitude of 1. This means that they are a complete set of unit vectors, which can simplify calculations even further.

Can a complete orthogonal system have more than three dimensions?

Yes, a complete orthogonal system can exist in any number of dimensions. However, visualizing it becomes increasingly difficult as the number of dimensions increases beyond three.

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