- #1
semidevil
- 157
- 2
so let H = { 0, 3, 6} under Z(9), and I need to find a + H.
the book shows
0 + H = 3 + H = 6 + H
1 + H = 4 + H = 7 + H
2 + H = 5 + H = 8 + H.
I"m not understanding why they start with 0, 1, 2. what gives that away?
the book shows
0 + H = 3 + H = 6 + H
1 + H = 4 + H = 7 + H
2 + H = 5 + H = 8 + H.
I"m not understanding why they start with 0, 1, 2. what gives that away?