- #1
Recce
- 6
- 0
y = 3e^(−2x) −5e^(−4x)
y'= −6e^(−2x)+20e^(−4x)
How do I find the critical point at x?
The answer is (1/2)ln(10/3) but I don't know how to get that answer
Thank you
y'= −6e^(−2x)+20e^(−4x)
How do I find the critical point at x?
The answer is (1/2)ln(10/3) but I don't know how to get that answer
Thank you