Finding Current and B Field given J(p) in Z Direction

In summary, the current density is given by J(p) = (I/pi) * p^2 * e^(-p^2) in the z direction. The question is to show that the total current flowing through the wire is 'I' and then find the magnetic field using Stokes' theorem. The attempt at a solution involves setting up the problem in cylindrical coordinates and integrating from 0 to infinity, but there may be an error in the integration steps.
  • #1
iontail
24
0

Homework Statement



the current density is given by J(p) = (I/pi) * p^2 * e^(-p^2) in z direction
The question is to first show that the cureent flowing through the wire is 'I' and then to find then to find the B field.

Homework Equations



stokes theorem.
integral of B.dl = I

I = J.dS

The Attempt at a Solution



i can find the magnetic field. however i am stuck on the first part that requires me to proof the total current is I.
I set up the problem in cylindrical coordinates and tired the double integration between 0 to 2pi and o to a(arbitsry distance) however this does not give the correct result. plese point me in the right direction
 
Last edited:
Physics news on Phys.org
  • #2
Hi iontail,

iontail said:

Homework Statement



the current density is given by J(p) = (I/pi) * p^2 * e^(-x^2) in z direction
The question is to first show that the cureent flowing through the wire is 'I' and then to find then to find the B field.

Homework Equations



stokes theorem.
integral of B.dl = I

I = J.dS

The Attempt at a Solution



i can find the magnetic field. however i am stuck on the first part that requires me to proof the total current is I.
I set up the problem in cylindrical coordinates and tired the double integration between 0 to 2pi and o to a(arbitsry distance) however this does not give the correct result. plese point me in the right direction

Can you verify your equation? You have:

J(p) = (I/pi) * p^2 * e^(-x^2)

Is that supposed to be p^2 in the exponential instead of x^2? Also, can you show your work for the integration?
 
  • #3
sorry about that it is supposed to b p^2, a typo. I tried integrating by parts on the ,p, terms and using the cylindrical coordinates formula for for dS. I get e^-p(p+3) as result
 
  • #4
i updated the question as well
 
  • #5
iontail said:
sorry about that it is supposed to b p^2, a typo. I tried integrating by parts on the ,p, terms and using the cylindrical coordinates formula for for dS. I get e^-p(p+3) as result

I don't believe the integral should be cut off at an arbitrary limit (like you are doing with the quantity a); instead the radial varible p should be integrated from 0 to infinity. If you are still getting the wrong answer, please post the integration steps you are taking.
 

FAQ: Finding Current and B Field given J(p) in Z Direction

1. What is the equation for finding the current in the z-direction given J(p)?

The equation for finding the current in the z-direction is I(z) = ∫ J(p) dp, where J(p) is the current density and dp is the differential volume element.

2. How can I find the magnetic field in the z-direction using the current density in the same direction?

To find the magnetic field in the z-direction, you can use the Biot-Savart law which states that B(z) = (μ0/4π) ∫ (J(p) x r̂)/r^2 dp, where μ0 is the permeability of free space, J(p) is the current density, r̂ is the unit vector in the direction of the current, and r is the distance between the current element and the point where the magnetic field is being calculated.

3. Is there a simplified version of the equation for finding the current and magnetic field in the z-direction?

Yes, there is a simplified version of the equation for finding the current and magnetic field in the z-direction. If the current density is constant, you can use the equations I(z) = J(z) * A and B(z) = (μ0/2π) * J(z), where A is the cross-sectional area perpendicular to the current flow and J(z) is the constant current density in the z-direction.

4. How does the direction of the current affect the direction of the magnetic field?

The direction of the current affects the direction of the magnetic field according to the right-hand rule. The direction of the magnetic field is perpendicular to both the direction of the current and the direction of the current element.

5. Can I use this equation to find the current and magnetic field in directions other than the z-direction?

Yes, the equations for finding the current and magnetic field can be applied to any direction. You just need to take into account the direction of the current and the current element when using the Biot-Savart law and the right-hand rule to determine the direction of the magnetic field.

Similar threads

Back
Top