Finding Curve γ(t) on M with Given Parameters

In summary, the conversation discussed finding a curve on the surface M parametrized by x(u,v) = (u, v, u2 - v2) with a given point P and tangent vector v. The v in the parametrization is a point in the tangent plane at P, and a distinction needs to be made between it and the tangent vector v. The conversation also mentioned the use of a template and filling it in to provide a solution.
  • #1
Shackleford
1,656
2
Consider the surface M parametrized by x(u,v) = (u, v, u2 - v2) and let P=(1,1,0)[itex] \in M[/itex]. Let v = ([itex]\frac{7}{2},2,3) \in T_p(M).[/itex]

(a) Find a curve γ : I → M with γ(0) = P, γ'(0) = v and write γ(t) = x(u(t), v(t)), i.e. you need to find out what is u(t) and v(t).

Eh. I'm not quite sure how to find the curve γ(t). I think that the problem is probably a bit easier being given the parametrization of M. I do know that the point P lies in the xy-plane.
 
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  • #2
Et tu, Shackle: Did you notice PF has a template ?

I have no clue what you mean with ##v =(\frac{7}{2},2,3) \in T_p(M)##.
Enlighten me, and all those others who might want to help you...
 
  • #3
BvU said:
Et tu, Shackle: Did you notice PF has a template ?

I have no clue what you mean with ##v =(\frac{7}{2},2,3) \in T_p(M)##.
Enlighten me, and all those others who might want to help you...

It's the tangent plane of M at P.
 
  • #4
Good. While you are explaining anyway, is the v in x(u,v) = (u, v, u2 - v2) also a point in this tangent plane ?
 
  • #5
BvU said:
Good. While you are explaining anyway, is the v in x(u,v) = (u, v, u2 - v2) also a point in this tangent plane ?

The v is in the tangent plane, not necessarily in the surface, right?
 
  • #6
My guess is that there are two v floating around in the problem statement, and you need to make a distinction between them. Nice opportunity to catch up with the requirement to make use of the template!

1. The problem statement, all variables and given/known data


Homework Equations




The Attempt at a Solution

 
  • #7
BvU said:
My guess is that there are two v floating around in the problem statement, and you need to make a distinction between them. Nice opportunity to catch up with the requirement to make use of the template!

1. The problem statement, all variables and given/known data


Homework Equations




The Attempt at a Solution


Yes, the v is a vector in the tangent plane, not the parameter v.
 
  • #8
Brilliant evasion of the chore to fill in the template. As if we're among real experts.
So now you have ##\gamma(0)## as a given, yielding you u(0) and v(0).
Your turn for ##\gamma'(0)##
 

FAQ: Finding Curve γ(t) on M with Given Parameters

What is the purpose of finding curve γ(t) on M with given parameters?

The purpose of finding curve γ(t) on M with given parameters is to determine a specific path on a manifold M that satisfies certain criteria or constraints.

What are the parameters used to define curve γ(t)?

The parameters used to define curve γ(t) on M can vary depending on the specific problem, but they typically include the starting point, ending point, and any other constraints or conditions that must be satisfied.

How is the curve γ(t) found on a manifold M?

The curve γ(t) on a manifold M can be found using mathematical techniques such as calculus and differential equations. These methods involve minimizing a certain functional or equation in order to find the optimal path on the manifold.

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Finding curve γ(t) on M is significant because it allows for the optimization of paths on a manifold, which has many real-world applications in fields such as physics, engineering, and computer graphics.

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