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projection
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Homework Statement
Let [tex]y=\sqrt{x+f(x^2-1)}[/tex]. Find [tex]\frac{dy}{dx}[/tex] when x=3, given that [tex]f(8)=0[/tex] and [tex]f'(8)=3[/tex].I missed the lesson for this and am lost on what to do. some guidence would be appreciated. i don't understand the [tex] f(x^2-1) [/tex] inside the bracket.
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