- #1
Dustinsfl
- 2,281
- 5
$$
\mathcal{J} = \begin{pmatrix}
-\sigma & \sigma & 0\\
1 & -1 & -\sqrt{b(r - 1)}\\
\sqrt{b(r - 1)} & \sqrt{b(r - 1)} & - b
\end{pmatrix}
$$
From a quick try and error, I was able to find that when $r = 1.3456171$ we will have 3 negative eigenvalues.
But when $r = 1.3456172$, there will be a complex-conjugate pair of eigenvalues.
Is there a mathematically more elegant way to determine this r value?
$b = \frac{8}{3}$ and $\sigma = 10$
\mathcal{J} = \begin{pmatrix}
-\sigma & \sigma & 0\\
1 & -1 & -\sqrt{b(r - 1)}\\
\sqrt{b(r - 1)} & \sqrt{b(r - 1)} & - b
\end{pmatrix}
$$
From a quick try and error, I was able to find that when $r = 1.3456171$ we will have 3 negative eigenvalues.
But when $r = 1.3456172$, there will be a complex-conjugate pair of eigenvalues.
Is there a mathematically more elegant way to determine this r value?
$b = \frac{8}{3}$ and $\sigma = 10$