- #36
RandallB
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I appreciate the effort, but allow me to correct a couple points. Although your analysis is a bit short on detail, I can see enough to point out your errors with a couple specific measurements.kev said:I personally like to think there is a Einstien local multiple hidden variable solution to the Bell inequality type experiments but unfortunately this does not appear to be it.
First – In reference to a “local multiple hidden variable solution”; what I’ve described in post # 7 is a two variable solution. Using a previously unknown (but still hidden from direct & complete measurement) variable by revising the polarization description of an individual Photon and Photon pairs in the case of Type II PDC. The key is EPR-Bell must use TWO variables, the well known Mauls description of light polarization, plus my fixed width description of photons. As I’ve said the Logic of the Bell Theorem can only deny the possibility of a single variable.
Now to your Analysis:
For the “Sunglasses” multi filter Vert. Hrzt. Vs. Vert. Diag. Hrzt paradox.
By “so far so good”, your are saying that you agree: Instead of using a non-local probability at a second filter to decided if an individual photon shall pass that filter; my locally defined value established at the prior filter has preset within the photon if it will pass any given future polar measurement. A successful “Einstein-Local” solution to the Sunglasses paradox.kev said:Analysis:
Light passing through 1 polarizing filter = 1/2 Pass
Light passing through 2 polarizing filters at 45 degrees to each other = 1/4 Pass
Light passing through 2 polarizing filters at 90 degrees to each other = 0 Pass
Light passiing through 3 polarizing filters at +45 degress in succession = 1/8 Pass
So far, so good.
Now for using my Hidden Variable PDC test using four test areas A1 & A2 with there paired photons in B1 & B2.
kev said:PDC Bell type test. Alice and Bob's polarizing filters aligned with each other.
Number of photons detected at the same time by Alice and Bob = 0. Fail.
Number of photons detected by Alice but not by Bob =1. Fail.
Number of photons detected by Bob but not by Alice =1. Fail.
The graph from 0 to 90 degrees would appear to be a straight line in the opposite direction to the basic single hidden variable graph.
This is way off, what you are describing here MATCHS not fails to match the QM predictions. If Alice and Bob both measure at the same angle such as 0° or Vertical; Alice will only see V photons paired with H photons on Bob side and with Bob’s measurements in the same vertical alignment he can never see those H photons. i.e. detected at the same time as ALL expect QM included. That is the definition of Type II PDC and QM agrees with that. Your comment about “opposite direction” tells me you are getting confused by the unfortunate practice of allowing Bob to define Horizontal as 0° instead of 90° when collecting his results. That means 0° by Alice vs. 0° by Bob giving 100% correlations is in fact a 90° measurement separation as I describe.
Much better to insist that Bob use the same “compass” measurements as Alice, so you do not get confused like that. I makes it easier to track the locations of paired photons e.g. if Alice makes a set of measurements at 22° with a sample that expects 100 V photons and 100 H photons to come by her test area(s) she would see 86 V’s and 14 H’s half the total of 200. We know at any angle she will always see one half of the total 200 photons, detecting a normal beam of polarized light at that angle and not detecting the other half. Now Bob by QM definition expects to find 100% correlation with those at 112° (or 22° if Bob resets 0° to horizontal) a 90° separation of measurement. At that angle Bob will find 14 V’s in B2 paired with 14 H’s Alice saw. Bob also finds 86 H’s in the B1 test area paired with the 86 V’s Alice saw. These are the only 100 photons Bob will see of the 200 passing his test area(s). And when you copy over the polarization shape of each of those 100 photons based on my local hidden variable for photons defined in Post #7, a normal looking beam of polarized light this time aligned at 112° is defined. And against just this group of photons if Bob had measured at any other angle the count of detections would follow Malus. Therefore even though Bob will always count 100 photons at any angle, he will only correlate with Alice’s detections based on Malus’ Law at other angles. Including + or - 90° from 112° for Zero correlations when Bob measures at the same angle that Alice did 22° or 202°.
In other words it successfully predicts the violation of the Bell inequities, all based a two sets of Local Variables. One already known variable defining Light polarization by Malus and my definition of fixed photon polarization no probabilities required. The only probabilities needed are the locally defined ones in Malus.
I have no idea how you came up with “=2/3 Fail” the correct answer using my HV is 3/4. And QM does not expect 25%, it instead matches my prediction with 75%. A 120° advance by Bob beyond Alice’s measurement at 22° would be 142° or 60° separation from Alice’s test at 22° (aka 202°). For Bob his 142° test is only 30° away from 112° where he would measure the max 100% correlations. Both QM and my approach expect Malus (Cos 30)^2 to apply giving 75% not 1/4.kev said:PDC Bell type test. Alice and Bob's polarizing filters at 120 degrees to each other.
-Number of photons detected at the same time by Alice and Bob =2/3. Fail.
The proportion should be 1/4 to agree with QM.
I am sure when you redo your analyses carefully you will find this is an affective Einstein Local solution to the EPR-Bell paradox just as you found it to be so for the “Sunglasses Paradox”.
Randall B