Finding explicit maximal solution of an IVP using Exact Diff Eqs

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In summary, the conversation discusses finding the explicit maximal solution of an IVP using exact differential equations. The IVP is given and the first step is to obtain the implicit solution. The conversation then explains the process for solving it implicitly and obtaining the explicit solution. The next step is to determine the maximal open interval on which the explicit solution is defined. However, there is confusion about this concept and the conversation ultimately gives the solution of (-inf, inf) where sinx is not equal to -1.
  • #1
nathancurtis111
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I need to find the explicit maximal solution of an IVP using exact Diff Eqs:

The IVP is given as:

{xexyy'-cos(x)+yexy=0
{y(0)=1

So I know at first I need to get the implicit solution by getting that:
A(x,y) = xexy
B(x,y) = -cos(x)+yexy

I know I need to find the partial derivative of A(x,y) with respect to x then the partial derivative of B(x,y) with respect to y.

After this I can't quite figure out how to get this one solved implicitly first, but the real problem lies with getting it explicitly defined (hence giving us the explicit maximal solution) and the maximal open interval after that.
 
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  • #2
I would first write the ODE in differential form:

\(\displaystyle \left(ye^{xy}-\cos(x) \right)dx+\left(xe^{xy} \right)dy=0\)

Next we need to compute:

\(\displaystyle \frac{\partial}{\partial y}\left(ye^{xy}-\cos(x) \right)=e^{xy}(xy+1)\)

\(\displaystyle \frac{\partial}{\partial x}\left(xe^{xy} \right)=e^{xy}(xy+1)\)

Thus, we see that the ODE is exact. And so we must have:

\(\displaystyle \frac{\partial F}{\partial x}=ye^{xy}-\cos(x)\)

Integrate this with respect to $x$ to get:

(1) \(\displaystyle F(x,y)=\int ye^{xy}-\cos(x)\,dx+g(y)\)

To determine $g(y)$, take the partial derivative with respect to $y$ of both sides and substitute \(\displaystyle xe^{xy}\) for \(\displaystyle \frac{\partial F}{\partial y}\). Then solve for $g'(y)$ to obtain $g(y)$ up to a numerical constant. Then substitute for $g(y)$ in (1) to obtain $F(x,y)$. The solution to the ODE is then given implicitly by:

\(\displaystyle F(x,y)=C\)

So, what do you find?
 
  • #3
Okay so I implicitly solved it and got:

exy-sin(x)=1

Then I was able to pretty easily solve it explicitly from there:

\(\displaystyle y=(ln|1+sin(x)|)/x\)

Now after this I need to find the maximal open interval and that's where I'm really really stuck.
 
  • #4
Looking at my notes, 0 is supposed to be included because its a solution to begin the problem, yet 0 is undefined in this specific case if the above explicit solution is correct. So, I'm a bit confused even more so now.
 
  • #5
Perhaps this is overcome by:

\(\displaystyle \lim_{x\to0}\frac{\ln(1+\sin(x))}{x}=1\)

I am unfamiliar with the term "maximal explicit solution" so I would wait until someone who is familiar with it can weigh in. :D
 
  • #6
So the maximal solution was basically just asking on what open interval is the explicit solution maximized (so basically the maximum domain on which it is defined on) on including the original initial condition. What really confused me though is the fact that there is an infinite amount of numbers in which (sin x) was not equal to -1, therefore defined, and also an infinite amount of numbers in which (sin x) was equal to -1, therefore undefined. So I ended up just giving the solution (-inf, inf) where sinx is not equal to -1 and got full credit. :D
 
  • #7
nathancurtis11 said:
So I ended up just giving the solution (-inf, inf) where sinx is not equal to -1 and got full credit. :D

Just a small note here: it is MHB policy not knowingly to help with any problem that counts towards a student's grade. Best thing to do is ask for help on a similar problem to one on which you are stuck.
 

FAQ: Finding explicit maximal solution of an IVP using Exact Diff Eqs

What is an initial value problem (IVP)?

An initial value problem involves finding a solution to a differential equation that satisfies a given set of initial conditions. The initial conditions typically include a specific point on the solution curve, as well as the slope or derivative at that point.

What is a maximal solution to an IVP?

A maximal solution to an IVP is the largest possible interval of values for which a solution exists. This solution must also satisfy the differential equation and the initial conditions.

What are explicit solutions to differential equations?

An explicit solution is a form of solution that can be expressed in terms of known functions, such as polynomials, exponentials, and trigonometric functions. This is in contrast to implicit solutions, which cannot be expressed in terms of known functions.

What is the role of exact differential equations in finding maximal solutions to an IVP?

Exact differential equations are used to find explicit maximal solutions to an IVP. They involve finding a potential function that satisfies a specific condition, which allows for an explicit solution to be obtained.

What are some methods for finding explicit maximal solutions of an IVP using exact differential equations?

One method is to use the method of separation of variables, where the equation is rewritten in a form that allows for the variables to be separated and an explicit solution to be found. Another method is to use integrating factors, which involves multiplying the entire equation by a specific function to make it exact.

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