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jdawg
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Finding F1 -- Summing forces on a box
There are two forces on the 2.80 kg box in the overhead view of the figure but only one is shown. For F1 = 10.9 N, a = 10.2 m/s2, and θ = 34.9°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
I'm not sure if this link will work, but here's the picture: http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c05/fig05_32.gif
∑F=ma
∑F=F1+F2...+
Ok so I've been stuck on this one for a while. I started out finding the sum of the forces:
∑F=(2.8kg)(10.2m/s2)=28.56 N
Then I tried solving for F2:
28.56N=10.9N+F2
F2=17.66
Then I found the x and y components of the acceleration:
ax=10.2*sin(34.9)=5.84m/s2
ay=10.2*cos(34.9)=8.37m/s2
Could you multiply ax and ay by the mass and get the F1x and F1y?
I'm so confused, could someone please help guide me through this problem?
Homework Statement
There are two forces on the 2.80 kg box in the overhead view of the figure but only one is shown. For F1 = 10.9 N, a = 10.2 m/s2, and θ = 34.9°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
I'm not sure if this link will work, but here's the picture: http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c05/fig05_32.gif
Homework Equations
∑F=ma
∑F=F1+F2...+
The Attempt at a Solution
Ok so I've been stuck on this one for a while. I started out finding the sum of the forces:
∑F=(2.8kg)(10.2m/s2)=28.56 N
Then I tried solving for F2:
28.56N=10.9N+F2
F2=17.66
Then I found the x and y components of the acceleration:
ax=10.2*sin(34.9)=5.84m/s2
ay=10.2*cos(34.9)=8.37m/s2
Could you multiply ax and ay by the mass and get the F1x and F1y?
I'm so confused, could someone please help guide me through this problem?