Finding Force Exerted by Photons on a Sphere

In summary, the sphere completely absorbs the photons falling on it and the force exerted on it is the same.
  • #1
cupid.callin
1,132
1
I was given this question in my book …
A sphere of radius 1cm is placed in path of light of large aperture. The intensity of light is 0.5W/cm^2. The sphere completely absorbs photons falling on it. Find the force exerted by them on the sphere.
I solved the question and I have given the solution in the pic. Please have a look.

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Next there was another question given below it …
The same sphere is placed in same light but this time the sphere is not perfectly absorbing. Show that the force exerted by photons remains the same.

Well I have no idea how to prove the second one. Please someone help .
 
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  • #2
that is easy, but you need a little more complicated calculus.
i think that this time it is a perfectly reflecting surface (a mirror) than it will reflect photons in all directions. there will be a spherical symetry, we can consider rings which will have same reflecting angles starting from r=0 to r=R (radius of sphere)
for an arbitrary r angle that is between line that is parallel to path of photons and normal is arcsin(r/R)
the area of that ring is 2(pi)rdr
if you draw what i explained, you will see that angle of reflected photon is 2.arcsin(r/R) call this angle 2(theta)
so momentum of one of reflected photons is -(h/lambda)cos(2theta) right? i couldn't follow your notation but let's assume there are n photons per unit area
Ptotalx=int(0toR) [-2(pi)n.r.h.cos(2arcsin(r/R))/lambda]dr
that will give sum of x components of momentums of reflected photons, you need deltaP to find force
it is Pinitial-Pfinal. Pfinal is result of the integral, P initial is what you found on you paper. I am sure you will understand the concept because at you notes you have wrote that Pfinal is 0 since photons are absorbed, here it is simple not zero. But these two do never give the same result.
 
  • #3
Thanks a lot sigmaro!

I really helped ... question is solved!
 

FAQ: Finding Force Exerted by Photons on a Sphere

What is the equation for calculating the force exerted by photons on a sphere?

The equation is F = (2 * P) / c, where F is the force, P is the power of the photon source, and c is the speed of light.

How is the force exerted by photons on a sphere different from other types of forces?

The force exerted by photons on a sphere is a non-contact force, meaning it does not require physical contact between the photons and the sphere. It is also a very small force, typically measured in micro or nano-Newtons.

Is the force exerted by photons on a sphere constant?

No, the force exerted by photons on a sphere decreases as the distance between the photon source and the sphere increases. This is due to the inverse square law, which states that the intensity of light decreases as the distance from the source increases.

How does the material of the sphere affect the force exerted by photons?

The material of the sphere can affect the force exerted by photons in two ways. First, the material's reflectivity can impact the amount of photons that are absorbed versus reflected, thus changing the overall force. Second, the material's index of refraction can affect the direction of the photons, which can also impact the force exerted.

Can the force exerted by photons on a sphere be measured experimentally?

Yes, the force exerted by photons on a sphere can be measured experimentally using a variety of techniques such as optical tweezers or radiation pressure experiments. These experiments can help us better understand the behavior of photons and their interactions with matter.

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