- #1
dannyboy8920
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Hey, I am a student in first year of college, going through some of my exam review questions the teacher gave us to polish up on before the exam. would appreciate the help, its probably a really easy question; but I am just getting into physics...went through a bunch of differerent things.
A horizontal force of 5.0N accelerates a 4.0kg mass, from rest, at a rate of 0.50m/s^2 in the positive direction. what friction force acts on the mass.
I know that F(friction)=uFN, =u(ma)
where I am getting stuck is that i don't have the coefficient to find the FF
I further looked, and not sure if this the right way to do it.
Im given the F of 5.0N ...do i just do F=ma, so =(4.0kg)(.50m/s^2) =2N...
Do i just find the difference in them?; so 5.0N-2.0N =3N.
Homework Statement
A horizontal force of 5.0N accelerates a 4.0kg mass, from rest, at a rate of 0.50m/s^2 in the positive direction. what friction force acts on the mass.
Homework Equations
I know that F(friction)=uFN, =u(ma)
where I am getting stuck is that i don't have the coefficient to find the FF
The Attempt at a Solution
I further looked, and not sure if this the right way to do it.
Im given the F of 5.0N ...do i just do F=ma, so =(4.0kg)(.50m/s^2) =2N...
Do i just find the difference in them?; so 5.0N-2.0N =3N.