- #1
chriss85
- 3
- 0
hello.
I'm looking for some general guidance as to which methods to use where.
i'm wanting to find the force vectors on an object as it moves along a general curve in a space (imagine a roller coaster). for example the parametric curve.
z=t
x=cos(t)
y=sin(t)I know i need to find the partial derivatives of the curve to find the gradient vector and the directional derivative. finding that isn't an issue.
i'm stuck now where i keep wanting to jam the vector R= (R+VT+1/2AT^2)<i,j,k>
head on with the R(t) vector for the curve.
and because of that i can visualize vector components of gravity. i think its one of those things that's right in front of me and I'm just not seeing it. most likely the changing acceleration is what's throwing me off.
once i have F(g)(x,y,z) and the direction, that will give me F(n) and f(k). and from that all i need is (S) to find the work done. after that there's F(c) which I'm expecting to also be a pain.i'm in the process of coding this and all that's left to finish is this bit.
thanks.
chris
I'm looking for some general guidance as to which methods to use where.
i'm wanting to find the force vectors on an object as it moves along a general curve in a space (imagine a roller coaster). for example the parametric curve.
z=t
x=cos(t)
y=sin(t)I know i need to find the partial derivatives of the curve to find the gradient vector and the directional derivative. finding that isn't an issue.
i'm stuck now where i keep wanting to jam the vector R= (R+VT+1/2AT^2)<i,j,k>
head on with the R(t) vector for the curve.
and because of that i can visualize vector components of gravity. i think its one of those things that's right in front of me and I'm just not seeing it. most likely the changing acceleration is what's throwing me off.
once i have F(g)(x,y,z) and the direction, that will give me F(n) and f(k). and from that all i need is (S) to find the work done. after that there's F(c) which I'm expecting to also be a pain.i'm in the process of coding this and all that's left to finish is this bit.
thanks.
chris