Finding Force with friction on a slope

In summary, the homework statement is that the angle Φ is not correctly indicated in your diagram, and the attempt at a solution refers to the use of a picture to help clarify the problem. The homework equation is correctly drawn, but the angle Φ is not correctly indicated.
  • #1
PAstudent
47
0
image.jpg
1. Homework Statement

I was wondering if my phi angle was in the right position from the picture. Also, it is correct that my normal force FN is perpendicular to the surface?

Homework Equations


Newton's second law
fk=ukFN[/B]

The Attempt at a Solution


Refer to picture[/B]
 
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  • #2
The angle Φ is not correctly indicated in your diagram. Note that Φ is the angle F makes to the vertical direction. Your normal force is correctly drawn.
 
  • #3
So the angle would just be on the other side of that Force vector
 
  • #4
I'm not sure exactly what you mean. Could you be more specific or attach another figure?
 
  • #5
image.jpg
 
  • #6
That's still not quite right. You now have Φ as the angle between F and your y axis. But Φ is the angle between F and the vertical direction.
 
  • #7
I get what you are saying about the vertical direction, but I just don't get how that vector wouldn't be in that quadrant
 
  • #8
You have F in the correct quadrant of your x-y coordinate system. But you do not have the angle Φ indicated correctly. Φ is not the angle between F and the y axis. Φ is the angle between F and the vertical direction. The vertical direction is along the same line that mg acts. Draw a dotted line along mg and extend it upward into the same quadrant that F is in.
 
  • #9
image.jpg
 
  • #10
You rotated F to the wrong side of the vertical. In the original figure, F points up and to the left. You now have F pointing up and to the right.
 
  • #11
image.jpg

Hopefully this is correct. Sorry to put you through all of that. I just struggle with these type of angle concepts
 
  • #12
Yes, your free body diagram is now correct. You just need to find the angle that F makes to the x-axis (or y axis).
 
  • #13
Thank you for all your help
 

FAQ: Finding Force with friction on a slope

1. How does friction affect the force on a slope?

The force of friction plays a crucial role in determining the overall force on an object on a slope. It acts in the opposite direction of the object's motion and can either increase or decrease the net force depending on the surface roughness and the weight of the object.

2. How do you calculate the force of friction on a slope?

The force of friction on a slope can be calculated using the formula Ff = μN, where Ff is the force of friction, μ is the coefficient of friction, and N is the normal force acting on the object. The coefficient of friction depends on the surface materials and the normal force is the component of the object's weight perpendicular to the slope.

3. What factors affect the force of friction on a slope?

The force of friction on a slope is affected by several factors, including the surface roughness and materials, the weight and shape of the object, and the angle of the slope. The coefficient of friction also varies depending on whether the surface is dry or wet.

4. How does the angle of the slope affect the force of friction?

The angle of the slope has a significant impact on the force of friction. As the slope increases, the force of friction also increases, making it more difficult for the object to move. At a certain angle, known as the angle of repose, the force of friction will be equal to the force of gravity, resulting in no motion.

5. Can you use the force of friction to determine the weight of an object on a slope?

Yes, the force of friction can be used to indirectly calculate the weight of an object on a slope. By measuring the force of friction and the angle of the slope, along with known values such as the coefficient of friction, the weight of the object can be calculated using trigonometry and Newton's second law of motion.

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