Finding formula for nth derivatives of some functions

In summary, the solution to this problem is to find the 1st, 2nd, and 3rd derivatives, and then find the pattern.
  • #1
member 731016
Homework Statement
Please see below
Relevant Equations
Please see below
For part(a),
1682634812514.png

The solution is,
1682654740676.png


However, I am having trouble understanding their finial formula. Does anybody please know what the floating ellipses mean? I have only seen ellipses that near the bottom like this ##...## I am also confused where they got the ##2 \cdot 1## from.

When solving this problem, in addition to finding the 1st and 2nd derivatives, I also found the 3rd and 4th derivatives, but I guess I didn't need the last two to find the pattern?

Many thanks!
 

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  • #2
The first one means "and so on until" and the second one means "multiplied by according factors until"
 
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  • #3
$$n!= 1\cdot 2 \cdot 3 \cdot \ldots \cdot (n-3)\cdot (n-2)\cdot (n-1)\cdot n $$
but there is no way to write down all factors in between since somewhere we will have to stop writing down natural numbers, and somewhere we will have to arrive at ##n.## The dots are for the factors in between.

Otherwise, we can only explain it by a recursion.
\begin{align*}
1! &= 1\\
n! &=n\cdot (n-1)!\text{ for all }n>1
\end{align*}

Now we have
$$
2!=2\cdot 1!=2\cdot 1=2 \Longrightarrow 3!=3\cdot 2!=3\cdot 2=6 \Longrightarrow \ldots \Longrightarrow n!=n\cdot (n-1)!=n\cdot (n-1)\cdot \ldots\cdot 2 \cdot 1
$$
The dots here mean: Insert the missing statements one by one, from the third to the ##(n-1)##th.
 
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Likes Kumail Haider, YouAreAwesome and member 731016
  • #4
ChiralSuperfields said:
Homework Statement: Please see below
Relevant Equations: Please see below

For part(a),
View attachment 325603
The solution is,
View attachment 325604
However, I am having trouble understanding their finial formula. Does anybody please know what the floating ellipses mean? I have only seen ellipses that near the bottom like this ##...## I am also confused where they got the ##2 \cdot 1## from.

When solving this problem, in addition to finding the 1st and 2nd derivatives, I also found the 3rd and 4th derivatives, but I guess I didn't need the last two to find the pattern?

Many thanks!
I read the three dots to mean, "Keeping following this pattern from my left, and you'll get this next thing to my right". My guess is this is not the official definition. 😀
 
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Likes member 731016

FAQ: Finding formula for nth derivatives of some functions

What is the nth derivative of a polynomial function?

The nth derivative of a polynomial function can be found by repeatedly applying the power rule. For a polynomial \( P(x) = a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0 \), the nth derivative is \( P^{(n)}(x) = n! a_n \) if \( n \) is the degree of the polynomial. For derivatives beyond the degree, the result is zero.

How do you find the nth derivative of the exponential function \( e^x \)?

The nth derivative of the exponential function \( e^x \) is simply \( e^x \). This is because the derivative of \( e^x \) is \( e^x \) itself, and this property holds for any number of differentiations.

What is the formula for the nth derivative of \( \sin(x) \) and \( \cos(x) \)?

The nth derivative of \( \sin(x) \) and \( \cos(x) \) follows a cyclic pattern due to their periodic nature. For \( \sin(x) \), the nth derivative is \( \sin(x + n\pi/2) \). For \( \cos(x) \), the nth derivative is \( \cos(x + n\pi/2) \).

How can the nth derivative of \( \ln(x) \) be determined?

The nth derivative of \( \ln(x) \) can be found using the formula: \( \frac{d^n}{dx^n} \ln(x) = (-1)^{n-1} \frac{(n-1)!}{x^n} \). This results from repeated application of the chain rule and the properties of logarithms.

What is Leibniz's rule for the nth derivative of a product of two functions?

Leibniz's rule provides a formula for the nth derivative of the product of two functions \( u(x) \) and \( v(x) \): \( (uv)^{(n)} = \sum_{k=0}^{n} \binom{n}{k} u^{(k)} v^{(n-k)} \). This rule is derived from the product rule and involves summing over all possible ways of distributing the derivatives between the two functions.

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